(编辑：jimmy 日期: 2024/11/13 浏览：2)
实现的功能类似MySQL：
show tables;
在 PostgreSQL 中需要写：
select * from pg_tables where schemaname = 'public';
返回结果类似如下：
schemaname | tablename | tableowner | tablespace | hasindexes | hasrules | hastriggers | rowsecurity ------------+-----------+------------+------------+------------+----------+-------------+------------- public | deploy | postgres | | t | f | f | f public | deploy2 | postgres | | f | f | f | f (2 rows)
补充：PostgreSql 获取所有的表、视图、字段、 主键
PostgreSQL获取数据库中所有view名 视图：
SELECT viewname FROM pg_views WHERE schemaname ='public'
postgreSQL获取数据库中所有table名 表：
SELECT tablename FROM pg_tables WHERE tablename NOT LIKE 'pg%' AND tablename NOT LIKE 'sql_%' ORDER BY tablename;
postgreSQL获取某个表tablename 所有字段名称 ， 类型，备注,是否为空 等
SELECT col_description(a.attrelid,a.attnum) as comment,pg_type.typname as typename,a.attname as name, a.attnotnull as notnull FROM pg_class as c,pg_attribute as a inner join pg_type on pg_type.oid = a.atttypid where c.relname = 'tablename' and a.attrelid = c.oid and a.attnum>0
postgreSQL获取某个表tablename 的主键信息
select pg_attribute.attname as colname,pg_type.typname as typename,pg_constraint.conname as pk_name from pg_constraint inner join pg_class on pg_constraint.conrelid = pg_class.oid inner join pg_attribute on pg_attribute.attrelid = pg_class.oid and pg_attribute.attnum = pg_constraint.conkey[1] inner join pg_type on pg_type.oid = pg_attribute.atttypid where pg_class.relname = 'tablename' and pg_constraint.contype='p'
以上为个人经验，希望能给大家一个参考，也希望大家多多支持。如有错误或未考虑完全的地方，望不吝赐教。