(编辑：jimmy 日期: 2024/11/19 浏览：2)
先给出结论：
replace()方法进行替换，效率非常高；replace() 进行替换。可行的方法：
1. 链式replace()
string.replace().replace()
1.x 在for循环中调用replace() 「在要替换的字符较多时」
2. 使用string.maketrans
3. 先 re.compile 然后 re.sub
……
def a(text):
chars = "&#"
for c in chars:
text = text.replace(c, "\\" + c)
def b(text):
for ch in ['&','#']:
if ch in text:
text = text.replace(ch,"\\"+ch)
import re
def c(text):
rx = re.compile('([&#])')
text = rx.sub(r'\\\1', text)
RX = re.compile('([&#])')
def d(text):
text = RX.sub(r'\\\1', text)
def mk_esc(esc_chars):
return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])
esc = mk_esc('&#')
def e(text):
esc(text)
def f(text):
text = text.replace('&', '\&').replace('#', '\#')
def g(text):
replacements = {"&": "\&", "#": "\#"}
text = "".join([replacements.get(c, c) for c in text])
def h(text):
text = text.replace('&', r'\&')
text = text.replace('#', r'\#')
def i(text):
text = text.replace('&', r'\&').replace('#', r'\#')
参考链接：
http://stackoverflow.com/questions/3411771/multiple-character-replace-with-python
http://stackoverflow.com/questions/6116978/python-replace-multiple-strings
http://stackoverflow.com/questions/8687018/python-string-replace-two-things-at-once
http://stackoverflow.com/questions/28775049/most-efficient-way-to-replace-multiple-characters-in-a-string
总结
以上就是这篇文章的全部内容了，希望本文的内容对大家学习或者使用python能有所帮在，如果有疑问大家可以留言交流。