(编辑：jimmy 日期: 2024/9/30 浏览：2)
本文实例讲述了PHP获得数组交集与差集的方法。分享给大家供大家参考。具体分析如下：
一、数组的交集 array_intersect()
array_intersect()函数返回一个保留了键的数组，这个数组只由第一个数组中出现的且在其他每个输入数组中都出现的值组成。其形式如下：
array array_intersect(array array1,array array2[,arrayN…])
下面这个例子将返回在$fruit1数组中出现的且在$fruit2和$fruit3中也出现的所有的水果：
<"Apple","Banana","Orange");
$fruit2 = array("Pear","Apple","Grape");
$fruit3 = array("Watermelon","Orange","Apple");
$intersection = array_intersect($fruit1, $fruit2, $fruit3);
print_r($intersection);
// output
// Array ( [0] => Apple )
"color: #0000ff">array array_intersect_assoc(array array1,array array2[,arrayN…])
下面的例子返回了出现在$fruit1数组中，也同时出现在$fruit2与$fruit3中的所有键/值对：
<"red"=>"Apple","yellow"=>"Banana","orange"=>"Orange");
$fruit2 = array("yellow"=>"Pear","red"=>"Apple","purple"=>"Grape");
$fruit3 = array("green"=>"Watermelon","orange"=>"Orange","red"=>"Apple");
$intersection = array_intersect_assoc($fruit1, $fruit2, $fruit3);
print_r($intersection);
// output
// Array ( [red] => Apple )
"color: #0000ff">array array_diff(array array1,array array2[,arrayN…])
实例如下：
<"Apple","Banana","Orange");
$fruit2 = array("Pear","Apple","Grape");
$fruit3 = array("Watermelon","Orange","Apple");
$intersection = array_diff($fruit1, $fruit2, $fruit3);
print_r($intersection);
// output
// Array ( [1] => Banana )
"color: #0000ff">array array_diff_assoc(array array1,array array2[,arrayN…])
下面的例子只返回了[yellow] => Banana,因为这个特殊的键/值对出现在$fruit1中，而在$fruit2和$fruit3中都不存在。
<"red"=>"Apple","yellow"=>"Banana","orange"=>"Orange");
$fruit2 = array("yellow"=>"Pear","red"=>"Apple","purple"=>"Grape");
$fruit3 = array("green"=>"Watermelon","orange"=>"Orange","red"=>"Apple");
$intersection = array_diff_assoc($fruit1, $fruit2, $fruit3);
print_r($intersection);
// output
// Array ( [yellow] => Banana )
?>
希望本文所述对大家的php程序设计有所帮助。