PHP正则验证Email的方法

<"@");
 if (is_bool($atIndex) && !$atIndex)
 {
  $isValid = false;
 }
 else
 {
  $domain = substr($email, $atIndex+1);
  $local = substr($email, 0, $atIndex);
  $localLen = strlen($local);
  $domainLen = strlen($domain);
  if ($localLen < 1 || $localLen > 64)
  {
   // local part length exceeded
   $isValid = false;
  }
  else if ($domainLen < 1 || $domainLen > 255)
  {
   // domain part length exceeded
   $isValid = false;
  }
  else if ($local[0] == '.' || $local[$localLen-1] == '.')
  {
   // local part starts or ends with '.'
   $isValid = false;
  }
  else if (preg_match('/\\.\\./', $local))
  {
   // local part has two consecutive dots
   $isValid = false;
  }
  else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain))
  {
   // character not valid in domain part
   $isValid = false;
  }
  else if (preg_match('/\\.\\./', $domain))
  {
   // domain part has two consecutive dots
   $isValid = false;
  }
  else if(!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+"\\\\","",$local)))
  {
   // character not valid in local part unless 
   // local part is quoted
   if (!preg_match('/^"(\\\\"|[^"])+"$/', str_replace("\\\\","",$local)))
   {
   $isValid = false;
   }
  }
  if ($isValid && !(checkdnsrr($domain,"MX") || checkdnsrr($domain,"A")))
  {
   // domain not found in DNS
   $isValid = false;
  }
 }
 return $isValid;
}
"color: #800000">PS：这里再为大家提供2款非常方便的正则表达式工具供大家参考使用：

JavaScript正则表达式在线测试工具：

http://tools.jb51.net/regex/javascript
正则表达式在线生成工具：

http://tools.jb51.net/regex/create_reg
希望本文所述对大家的php程序设计有所帮助。