(编辑:jimmy 日期: 2025/11/3 浏览:2)
本文实例讲述了PHP面向对象程序设计继承用法。分享给大家供大家参考,具体如下:
<"<p>$this->name : ",self::$count," : parent : __construct</p>";
}
function work(){
echo "<p>$this->name is working</p>";
}
function __destruct(){
echo "<p>parent unset $this->name</p>";
}
}
class Managers extends Employees{
private $pos = null;
function __construct($p,$nameStr){
parent::$count++;
parent::__construct($nameStr);
$this->pos = $p;
echo "<p>$this->name , $this->pos : self : __construct</p>";
}
function assignJob(){
echo "<p>$this->name assign jobs</p>";
}
function getName(){
return $this->name;
}
function __destruct(){
echo "<p>self unset $this->name</p>";
}
}
class Programmers extends Employees{
function code(){
echo "<p>$this->name is coding</p>";
}
function getName(){
return $this->name;
}
}
$e1 = new Employees('e1');
$e2 = new MAnagers(2,'e2');
$e3 = new Programmers('e3');
$e1->work();
$e2->work();
$e3->work();
$e2->assignJob();
$e3->Code();
echo "<p>{$e3->getName()}</p>";
//echo "<p>$e1->name</p>";
if($e2 instanceof Employees){
echo "<p>ok</p>";
}else{
echo "<p>no</p>";
}
unset($e1,$e2,$e3);
运行结果:
e1 : 0 : parent : __construct
e2 : 1 : parent : __construct
e2 , 2 : self : __construct
e3 : 1 : parent : __construct
e1 is working
e2 is working
e3 is working
e2 assign jobs
e3 is coding
e3
ok
parent unset e1
self unset e2
parent unset e3
更多关于PHP相关内容感兴趣的读者可查看本站专题:《php面向对象程序设计入门教程》、《PHP数组(Array)操作技巧大全》、《PHP基本语法入门教程》、《PHP运算与运算符用法总结》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》
希望本文所述对大家PHP程序设计有所帮助。